Answer this question from IQ exam
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Date: June 15th, 2017 12:01 AM Author: The Man on the Street
I don't get it.
First 2 columns are 3 green 2 green 1 green pattern, but column three is doing its own thing
This is rubbish
(http://www.autoadmit.com/thread.php?thread_id=3647923&forum_id=2#33560578) 
Date: June 15th, 2017 12:07 AM Author: boner_police
either far left or far right
eidt: far left
(http://www.autoadmit.com/thread.php?thread_id=3647923&forum_id=2#33560624) 

Date: June 15th, 2017 12:52 AM
Author: .;:..;:;.:.;.,,,.,.:,.;;,;;;..;,
maybe we're just supposed to notice the patterns in the individual boxes, so in the First Row (from L to R) > top row, middle row, middle row. Second Row (L to R) > middle, bottom, bottom. Last Row (L to R) > bottom, top, ***TOP***?
(http://www.autoadmit.com/thread.php?thread_id=3647923&forum_id=2#33560908) 

Date: June 15th, 2017 12:57 AM
Author: .,.,.;,.;.,.;:,,:,;.,,;,..;.,:,.,;;..:.,,.:.,:.::,
think it's this plus the fact that:
[max quantity of green in row]  [2nd largest quantity of green in row] = [min quantity of green in row]
so there would have to be two green boxes in the solution
this might jump through too many hoops though
(http://www.autoadmit.com/thread.php?thread_id=3647923&forum_id=2#33560949) 
Date: June 15th, 2017 11:06 AM
Author: .,,...,,...,.,....,..,,.,.
(http://www.autoadmit.com/thread.php?thread_id=3647923&forum_id=2#33563257) 
Date: June 15th, 2017 11:20 AM Author: Chaucer
everyone on here has an SAT >1500, and we can't solve this shit
spill the beans OP
(http://www.autoadmit.com/thread.php?thread_id=3647923&forum_id=2#33563376) 
Date: June 15th, 2017 11:30 AM
Author: .,.,......,.,.,:,,:,..,:::,....,:,,,.:.:.,:.::,..
lol it's an Irish IQ test. all answers are valid.
(http://www.autoadmit.com/thread.php?thread_id=3647923&forum_id=2#33563453) 
Date: June 15th, 2017 11:32 AM
Author: ...;.,,,,.....,.,,....;..,,,..
I think it's gotta be some mirror image along a diagonal or two. I'm too lazy to work it through but that's gotta be the answer.
(http://www.autoadmit.com/thread.php?thread_id=3647923&forum_id=2#33563465) 
Date: June 15th, 2017 12:03 PM Author: luxury communism
okay, here's the right answer. Can't believe I'm the one that actually figured it out.
if you look at it by row...all the green blocks are limited to just two of the lines with the largest amount of green blocks on a different line than the other blocks. So that leaves B and D as the remaining options.
Between those two D makes more sense because in each of the previous series the sum of each row equal each other (i.e., in the first series there are 3 blocks total on the top line and 3 blocks total on the second line).
Correct answer is D. HTH.
(http://www.autoadmit.com/thread.php?thread_id=3647923&forum_id=2#33563669) 

Date: June 15th, 2017 12:18 PM
Author: .,,...,,...,.,....,..,,.,.
This doesn't totally satisfy me, because the first two rows have a pattern of [same row, same row, 1 up row], but third row doesn't.
If the pattern is coincidence it's a shitty question.
(http://www.autoadmit.com/thread.php?thread_id=3647923&forum_id=2#33563806) 

Date: June 15th, 2017 12:27 PM
Author: ...;.,,,,.....,.,,....;..,,,..
the reason I hate questions like this is because you can work backwards to construct rules for any of the answers. What's the decision criteria to determine which rules are right?
(http://www.autoadmit.com/thread.php?thread_id=3647923&forum_id=2#33563894) 
Date: June 15th, 2017 12:34 PM Author: .,.,.,.,.,.,.,.,.,.,.,. (The kids are altright)
that is above my paygrade i give up
edit: this is really bothering me there is no discernible pattern
(http://www.autoadmit.com/thread.php?thread_id=3647923&forum_id=2#33563952) 
Date: June 15th, 2017 12:36 PM Author: don't run ihatecrime1@gmail.com mueller sees you (icu)
it's A
NUMBER OF BLOCKS:
both columns and rows have two grids where the green blocks add up to the max green block grid in that column/row, so answer has to be a two green block entry  leaves A or D
POSITIONING:
none of the columns have green blocks on the same row
all of the rows have two grids with green blocks on the same row, and one grid with green on a different row
only one satisfying both criteria is A
also it says "next in the sequence"  these are the only rules I can see that work both from top to bottom and left to right. the ppl saying D are only solving for the rows
(http://www.autoadmit.com/thread.php?thread_id=3647923&forum_id=2#33563969) 
Date: June 15th, 2017 12:48 PM
Author: ''"""'''"'"'
It's D. The pattern is: in each row of diagrams, add the number of total green squares that are on the same "level" (top, middle, or bottom). That sum is equal to the number of green squares that appear on a higher level in the remaining column.
Row 1: Column B and column C have green squares in the middle level. The sum of green squares in column B and C is three, and column A has 3 green squares on a higher level (top).
Row 2: Column B and column C have green squares in the bottom level. The sum of green squares in column B and C is two, and column A has 2 green squares on a higher level (middle).
Row 3: Column B has three squares on the highest level, so column A and C must, together, have three green squares on the same level. Column A has one green square on the bottom level, so we need two more green squares on the bottom level. That's D.
(http://www.autoadmit.com/thread.php?thread_id=3647923&forum_id=2#33564080) 

Date: June 15th, 2017 1:05 PM
Author: ''"""'''"'"'
Because in row 3, the most (possible) green squares appear in column B.
It's not column B + C = column A.
It's: column with the most green = column with less green + other column with less green.
(http://www.autoadmit.com/thread.php?thread_id=3647923&forum_id=2#33564254) 

Date: June 15th, 2017 1:09 PM Author: JFC
then the answer could just as easily be the leftmost square
look at it by columns:
column A: bottom + middle = top on a different row
column B: middle + top = bottom on a different row
column C: top + middle = 2 squares on a different row
(http://www.autoadmit.com/thread.php?thread_id=3647923&forum_id=2#33564282) 
Date: June 15th, 2017 12:57 PM Author: Mark Wohlers
It is unquestionably D and here's why. In each row and column (6 different ones of 3), the the two grids with the least amount of green squares equal the amount of green squares in the box with the most green squares. Test this for every row and column.
This leaves A and D as possible answers because the grid must have 2 green squares. Well also in every row (not column), the 2 grids with the fewest amount of green squares have their green squares on same row. That leaves D.
(http://www.autoadmit.com/thread.php?thread_id=3647923&forum_id=2#33564176) 
Date: June 15th, 2017 1:26 PM Author: Get Thee to the TRUMPery
I think it's A.
There definitely seems to be a summing pattern. As you go horizontally and vertically, there's a definite "bigger number and two addition partners" pattern. 3=2+1 and 2=1+1. So that means it's 2 green squares.
When you go horizontally, it seems to be that the left box has the green squares in one row, and the second two boxes have the green squares in a different (but same as each other) row. When you go vertically, the green squares are each in a different row. Both of those patterns are matched by A.
Edit: At first I thought D b/c then the 1 and 2 green boxes are on the same squares, but it wouldn't match the vertical pattern of them all being in different rows. If that makes sense.
(http://www.autoadmit.com/thread.php?thread_id=3647923&forum_id=2#33564413) 
Date: June 15th, 2017 1:37 PM Author: jerry garcia
A.
it's two squares because reading left to write in rows, you have 32=1, 21=1, and 13=2 (absolute value), so between A and D
2nd and 3rd columns are the same horizontal position, so A
(http://www.autoadmit.com/thread.php?thread_id=3647923&forum_id=2#33564516) 
Date: June 15th, 2017 10:12 PM Author: The Man on the Street
Awful question for the reason: the first two rows have a pattern wherein the # of green squares in the first two boxes moving leftward equals the # of boxes in the leftmost box (jumping up one row in the leftmost box).
Then the third row is randomly just square 1 + square 3 = square 2.
There are arguable reasons against D and *for* other choices.
This is a dogshit "Iq test" that probably cane out of a cereal box.
(http://www.autoadmit.com/thread.php?thread_id=3647923&forum_id=2#33569257)


